7b^2-41b+30=0

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Solution for 7b^2-41b+30=0 equation:



7b^2-41b+30=0
a = 7; b = -41; c = +30;
Δ = b2-4ac
Δ = -412-4·7·30
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*7}=\frac{12}{14} =6/7 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*7}=\frac{70}{14} =5 $

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